Copy only folders not files?

If you want to mirror a directory skeleton and copy no files:

find -type d -links 2 -exec mkdir -p "/path/to/backup/{}" \;

What's going on here:

• Find is only selecting directories
• We're using -links 2 to find the deepest possible directories.
• mkdir -p will make any missing directories along the way.

I've done it like this rather than find -type d -exec mkdir -p "/path/to/backup/{}" \; because it'll cut out on a whole buttload of mkdir calls. We can quickly prove this with a little test. Here's the test tree followed by what I ran to compare the two commands:

$ tree
.
├── dir1
│   ├── dir2
│   │   └── dir3
│   ├── dir7
│   └── dir8
└── dir9
    └── dir0

$ pr -m -t <(find -type d) <(find -type d -links 2)
.                               ./dir1/dir8
./dir1                          ./dir1/dir2/dir3
./dir1/dir8                     ./dir1/dir7
./dir1/dir2                     ./dir9/dir0
./dir1/dir2/dir3
./dir1/dir7
./dir9                  
./dir9/dir0 

And that's only going to get better in a real-word solution with thousands of directories.

Quite easily done with python one-liner:

bash-4.3$ tree
.
├── ABC
├── set_pathname_icon.py
├── subdir1
│   ├── file1.abc
│   └── file2.abc
├── subdir2
│   ├── file1.abc
│   └── file2.abc
└── subdir3
    └── subdir4
        └── file1.txt

4 directories, 7 files
bash-4.3$ python -c 'import os,sys;dirs=[ r for r,s,f in os.walk(".") if r != "."];[os.makedirs(os.path.join(sys.argv[1],i)) for i in dirs]' ~/new_destination
bash-4.3$ tree ~/new_destination
/home/xieerqi/new_destination
├── subdir1
├── subdir2
└── subdir3
    └── subdir4

As script this could be rewritten like so:

#!/usr/bin/env python
import os,sys
dirs=[ r for r,s,f in os.walk(".") if r != "."]
for i in dirs:
    os.makedirs(os.path.join(sys.argv[1],i))