Create ArrayList from array
Given:
Element[] array = new Element[] { new Element(1), new Element(2), new Element(3) };
The simplest answer is to do:
List<Element> list = Arrays.asList(array);
This will work fine. But some caveats:
- The list returned from asList has fixed size. So, if you want to be able to add or remove elements from the returned list in your code, you'll need to wrap it in a new
ArrayList
. Otherwise you'll get anUnsupportedOperationException
. - The list returned from
asList()
is backed by the original array. If you modify the original array, the list will be modified as well. This may be surprising.
new ArrayList<>(Arrays.asList(array));
(old thread, but just 2 cents as none mention Guava or other libs and some other details)
If You Can, Use Guava
It's worth pointing out the Guava way, which greatly simplifies these shenanigans:
Usage
For an Immutable List
Use the ImmutableList
class and its of()
and copyOf()
factory methods (elements can't be null):
List<String> il = ImmutableList.of("string", "elements"); // from varargs
List<String> il = ImmutableList.copyOf(aStringArray); // from array
For A Mutable List
Use the Lists
class and its newArrayList()
factory methods:
List<String> l1 = Lists.newArrayList(anotherListOrCollection); // from collection
List<String> l2 = Lists.newArrayList(aStringArray); // from array
List<String> l3 = Lists.newArrayList("or", "string", "elements"); // from varargs
Please also note the similar methods for other data structures in other classes, for instance in Sets
.
Why Guava?
The main attraction could be to reduce the clutter due to generics for type-safety, as the use of the Guava factory methods allow the types to be inferred most of the time. However, this argument holds less water since Java 7 arrived with the new diamond operator.
But it's not the only reason (and Java 7 isn't everywhere yet): the shorthand syntax is also very handy, and the methods initializers, as seen above, allow to write more expressive code. You do in one Guava call what takes 2 with the current Java Collections.
If You Can't...
For an Immutable List
Use the JDK's Arrays
class and its asList()
factory method, wrapped with a Collections.unmodifiableList()
:
List<String> l1 = Collections.unmodifiableList(Arrays.asList(anArrayOfElements));
List<String> l2 = Collections.unmodifiableList(Arrays.asList("element1", "element2"));
Note that the returned type for asList()
is a List
using a concrete ArrayList
implementation, but it is NOT java.util.ArrayList
. It's an inner type, which emulates an ArrayList
but actually directly references the passed array and makes it "write through" (modifications are reflected in the array).
It forbids modifications through some of the List
API's methods by way of simply extending an AbstractList
(so, adding or removing elements is unsupported), however it allows calls to set()
to override elements. Thus this list isn't truly immutable and a call to asList()
should be wrapped with Collections.unmodifiableList()
.
See the next step if you need a mutable list.
For a Mutable List
Same as above, but wrapped with an actual java.util.ArrayList
:
List<String> l1 = new ArrayList<String>(Arrays.asList(array)); // Java 1.5 to 1.6
List<String> l1b = new ArrayList<>(Arrays.asList(array)); // Java 1.7+
List<String> l2 = new ArrayList<String>(Arrays.asList("a", "b")); // Java 1.5 to 1.6
List<String> l2b = new ArrayList<>(Arrays.asList("a", "b")); // Java 1.7+
For Educational Purposes: The Good ol' Manual Way
// for Java 1.5+
static <T> List<T> arrayToList(final T[] array) {
final List<T> l = new ArrayList<T>(array.length);
for (final T s : array) {
l.add(s);
}
return (l);
}
// for Java < 1.5 (no generics, no compile-time type-safety, boo!)
static List arrayToList(final Object[] array) {
final List l = new ArrayList(array.length);
for (int i = 0; i < array.length; i++) {
l.add(array[i]);
}
return (l);
}