javascript palindrome without regex code example

Example 1: palindrome javascript

function palindrome(str) {
 var splitted = str.split("");
 var reversed = splitted.reverse("");
 var joined = reversed.join("");
 return joined.toLowerCase().replace(/[^0-9a-z]/gi, '') == str.toLowerCase().replace(/[^0-9a-z]/gi, '')
}

Example 2: How do you detect whether or not a word is a palindrome in javascript

function palindrome(str) {
  // Step 1. Lowercase the string and use the RegExp to remove unwanted characters from it
  var re = /[\W_]/g; // or var re = /[^A-Za-z0-9]/g;
  
  var lowRegStr = str.toLowerCase().replace(re, '');
  // str.toLowerCase() = "A man, a plan, a canal. Panama".toLowerCase() = "a man, a plan, a canal. panama"
  // str.replace(/[\W_]/g, '') = "a man, a plan, a canal. panama".replace(/[\W_]/g, '') = "amanaplanacanalpanama"
  // var lowRegStr = "amanaplanacanalpanama";
     
  // Step 2. Use the same chaining methods with built-in functions from the previous article 'Three Ways to Reverse a String in JavaScript'
  var reverseStr = lowRegStr.split('').reverse().join(''); 
  // lowRegStr.split('') = "amanaplanacanalpanama".split('') = ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"]
  // ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"].reverse() = ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"]
  // ["a", "m", "a", "n", "a", "p", "l", "a", "n", "a", "c", "a", "n", "a", "l", "p", "a", "n", "a", "m", "a"].join('') = "amanaplanacanalpanama"
  // So, "amanaplanacanalpanama".split('').reverse().join('') = "amanaplanacanalpanama";
  // And, var reverseStr = "amanaplanacanalpanama";
   
  // Step 3. Check if reverseStr is strictly equals to lowRegStr and return a Boolean
  return reverseStr === lowRegStr; // "amanaplanacanalpanama" === "amanaplanacanalpanama"? => true
}
 
palindrome("A man, a plan, a canal. Panama");