DataGridView Column Widths as Percentage
Try this
private void DgvGrd_SizeChanged(object sender, EventArgs e)
{
dgvGrd.Columns[0].Width = (int)(dgvGrd.Width * 0.2);
dgvGrd.Columns[1].Width = (int)(dgvGrd.Width * 0.2);
dgvGrd.Columns[2].Width = (int)(dgvGrd.Width * 0.4);
dgvGrd.Columns[3].Width = (int)(dgvGrd.Width * 0.2);
// also may be a good idea to set FILL for the last column
// to accomodate the round up in conversions
dgvGrd.Columns[3].AutoSizeMode = DataGridViewAutoSizeColumnMode.Fill;
}
Try using the DataGridViewColumn.FillWeight property. Basically you assign a weight to every column and the columns re-size according to those weights. The MSDN arcticle is not that great. See the below article for better explaination -
Presenting Data with the DataGridView Control in .NET 2.0—Automatic Column Sizing
Can use a value converter
This subtracts a parameter but you could have it divide by a parameter.
<local:WidthConverter x:Key="widthConverter"/>
<GridViewColumn Width="{Binding ElementName=lvCurDocFields, Path=ActualWidth, Converter={StaticResource widthConverter}, ConverterParameter=100}">
[ValueConversion(typeof(double), typeof(double))]
public class WidthConverter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
// value is the total width available
double otherWidth;
try
{
otherWidth = System.Convert.ToDouble(parameter);
}
catch
{
otherWidth = 100;
}
if (otherWidth < 0) otherWidth = 0;
double width = (double)value - otherWidth;
if (width < 0) width = 0;
return width; // columnsCount;
}
public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}