Decidability of periodic tilings of the plane

The answer appears to be no.

Consider first the case of the anchor-tile periodic tiling problem, where we insist that a particular anchor tile is used. Let's modify the usual Wang tile argument, due to Berger, for the oringal tiling problem. That argument shows that for any Turing machine program $p$, we can create a set of Wang tile types (square tiles with labels on the edges, to be matched up in a tiling) such that the operation of program $p$ corresponds directly to the pattern of tiles appearing in any tiling. Basically, the anchor row displays a complete picture of the Turing machine in the start configuration, and each subsequent row shows the configuraton after one additional step of computation using program $p$. The main idea of the scheme is that the tiling can continue as long as the program keeps running, and so there is a tiling if and only if the program does not halt. This is why the original anchor tiling problem is undecidable. (And the anchor feature was removed by a separate argument.)

But essentially the same idea can be used to solve your problem. We can modify the tiles involving the halt state so that a halting computation will support a periodic tiling. Basically, what is needed are tiles that will lead from a tile on which the program has halted to transform the next row to the initial configuration again. It would be a detailed thing to check, but after one has spent time using these Wang tiles to simulate Turing machine computations, this seems to be easily handled in the same way.

The end situation will be that if $p$ halts, then there will be a periodic tiling using the desired anchor tile, and if $p$ does not halt, then there will be no periodic tiling using that anchor tile. So the question will be undecidable.

Finally, it seems to me that one can remove the anchor tile requirement in the same way that is done with the original Wang tile argument (but this is a complication).