Decode JSON with unknown structure
package main
import "encoding/json"
func main() {
in := []byte(`{ "votes": { "option_A": "3" } }`)
var raw map[string]interface{}
if err := json.Unmarshal(in, &raw); err != nil {
panic(err)
}
raw["count"] = 1
out, err := json.Marshal(raw)
if err != nil {
panic(err)
}
println(string(out))
}
https://play.golang.org/p/o8ZwvgsQmoO
You really just need a single struct, and as mentioned in the comments the correct annotations on the field will yield the desired results. JSON is not some extremely variant data format, it is well defined and any piece of json, no matter how complicated and confusing it might be to you can be represented fairly easily and with 100% accuracy both by a schema and in objects in Go and most other OO programming languages. Here's an example;
package main
import (
"fmt"
"encoding/json"
)
type Data struct {
Votes *Votes `json:"votes"`
Count string `json:"count,omitempty"`
}
type Votes struct {
OptionA string `json:"option_A"`
}
func main() {
s := `{ "votes": { "option_A": "3" } }`
data := &Data{
Votes: &Votes{},
}
err := json.Unmarshal([]byte(s), data)
fmt.Println(err)
fmt.Println(data.Votes)
s2, _ := json.Marshal(data)
fmt.Println(string(s2))
data.Count = "2"
s3, _ := json.Marshal(data)
fmt.Println(string(s3))
}
https://play.golang.org/p/ScuxESTW5i
Based on your most recent comment you could address that by using an interface{}
to represent data besides the count, making the count a string and having the rest of the blob shoved into the interface{}
which will accept essentially anything. That being said, Go is a statically typed language with a fairly strict type system and to reiterate, your comments stating 'it can be anything' are not true. JSON cannot be anything. For any piece of JSON there is schema and a single schema can define many many variations of JSON. I advise you take the time to understand the structure of your data rather than hacking something together under the notion that it cannot be defined when it absolutely can and is probably quite easy for someone who knows what they're doing.