Defining an object without calling its constructor in C++
Store a pointer to an Object
rather than an actual Object
thus:
class Program
{
public:
Object* myObject; // Will not try to call the constructor or do any initializing
Program()
{
//Do initialization
myObject = new Object(...); // Initialised now
}
}
Don't forget to delete
it in the destructor. Modern C++ helps you there, in that you could use an auto_ptr shared_ptr rather than a raw memory pointer.
Others have posted solutions using raw pointers, but a smart pointer would be a better idea:
class MyClass {
std::unique_ptr<Object> pObj;
// use boost::scoped_ptr for older compilers; std::unique_ptr is a C++0x feature
public:
MyClass() {
// ...
pObj.reset(new Object(...));
pObj->foo();
}
// Don't need a destructor
};
This avoids the need to add a destructor, and implicitly forbids copying (unless you write your own operator=
and MyClass(const MyClass &)
.
If you want to avoid a separate heap allocation, this can be done with boost's aligned_storage
and placement new. Untested:
template<typename T>
class DelayedAlloc : boost::noncopyable {
boost::aligned_storage<sizeof(T)> storage;
bool valid;
public:
T &get() { assert(valid); return *(T *)storage.address(); }
const T &get() const { assert(valid); return *(const T *)storage.address(); }
DelayedAlloc() { valid = false; }
// Note: Variadic templates require C++0x support
template<typename Args...>
void construct(Args&&... args)
{
assert(!valid);
new(storage.address()) T(std::forward<Args>(args)...);
valid = true;
}
void destruct() {
assert(valid);
valid = false;
get().~T();
}
~DelayedAlloc() { if (valid) destruct(); }
};
class MyClass {
DelayedAlloc<Object> obj;
public:
MyClass() {
// ...
obj.construct(...);
obj.get().foo();
}
}
Or, if Object
is copyable (or movable), you can use boost::optional
:
class MyClass {
boost::optional<Object> obj;
public:
MyClass() {
// ...
obj = Object(...);
obj->foo();
}
};