Definition of sum of subspaces.

You are right that if you directly apply the definition, then $U+V = \{(x+y,y,0):x,y\in F\}$. However, $\{(x,y,0):x,y\in F\}$ and $\{(x+y,y,0):x,y\in F\}$ are the same set! Given any $(x,y,0)$ in the first set, if we let $z=x-y$ then $(x,y,0)=(z+y,y,0)$ so it is also in the second set. And given any $(x+y,y,0)$ in the second set, if we let $z=x+y$ then $(x+y,y,0)=(z,y,0)$ so it is also in the first set.