Deleting both values from array if duplicate - JavaScript/jQuery
EDITED with better answer:
var myArr = [1, 1, 2, 5, 5, 7, 8, 9, 9];
function removeDuplicates(arr) {
var i, tmp;
for(i=0; i<arr.length; i++) {
tmp = arr.lastIndexOf(arr[i]);
if(tmp === i) {
//Only one of this number
} else {
//More than one
arr.splice(tmp, 1);
arr.splice(i, 1);
}
}
}
Here's my version
var a = [1, 1, 2, 5, 5, 7, 8, 9, 9];
function removeIfduplicate( arr ) {
var discarded = [];
var good = [];
var test;
while( test = arr.pop() ) {
if( arr.indexOf( test ) > -1 ) {
discarded.push( test );
continue;
} else if( discarded.indexOf( test ) == -1 ) {
good.push( test );
}
}
return good.reverse();
}
x = removeIfduplicate( a );
console.log( x ); //[2, 7, 8]
jsfiddle for this code:
var myArr = [1, 1, 2, 5, 5, 7, 8, 9, 9];
var newArr = myArr;
var h,i,j;
for(h = 0; h < myArr.length; h++) {
var curItem = myArr[h];
var foundCount = 0;
// search array for item
for(i = 0; i < myArr.length; i++) {
if (myArr[i] == myArr[h])
foundCount++;
}
if(foundCount > 1) {
// remove repeated item from new array
for(j = 0; j < newArr.length; j++) {
if(newArr[j] == curItem) {
newArr.splice(j, 1);
j--;
}
}
}
}