Deleting first column with vim

This should delete all chars before and including the 1st tab on any line:

:%s/^[^\t]*\t//

Command line cut:

cut -f 2- {filename.txt} > {filenamenew.txt}

cut defaults to tabs; if you want something else like a space add -d " ". -f is fields to copy over. 2- means all from (and including) column 2.

Through awk,

awk -F"\t" '{print FS,$2}' file > newfile

It cuts the first column and prints only the remaining tab and second column.

Through sed,

sed -r 's/^([^\t]*)\t(.*)$/\t\2/g' file > newfile

:%s/[^\t]*\t//

On every line (%), replace (s/ORIGINAL/REPLACEMENT/) the first occurrence of “non-tab characters ([^\t], in any number (*)) followed by a tab \t” by nothing. You can type Tab instead of \t.

Alternatively you can match the shortest sequence of characters (.\{-}) ending in a tab. .*\t would match the longest match for .*, so it would match all but the last column; .\{-} matches the shortest match which is the first column.

:%s/.\{-}\t//