dictionary sort by value python code example

Example 1: how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Example 2: sort dict by value

dict(sorted(x.items(), key=lambda item: item[1]))

Example 3: python sort the values in a dictionary

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

Example 4: sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Example 5: sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Example 6: sorting-a-dictionary-by-value-then-by-key

[(14,2), (12,2), (9,1)]  # output from print 
[(90,4), (99,3), (101,1), (100,1), (92,1)]

Tags: