django admin, extending admin with custom views
This guide looks quite old. I would rather advise you to follow django docs.
someapp/admin.py
from django.contrib.admin import AdminSite
from django.http import HttpResponse
class MyAdminSite(AdminSite):
def get_urls(self):
from django.urls import path
urls = super().get_urls()
urls += [
path('my_view/', self.admin_view(self.my_view))
]
return urls
def my_view(self, request):
return HttpResponse("Hello!")
admin_site = MyAdminSite()
Source: https://github.com/django/django/blob/2.2/django/contrib/admin/sites.py#L194-L205
You should also update your project/urls.py
and replace path('admin/', admin.site.urls)
by path('admin/', admin_site.urls)
. Don't forget to from someapp.admin import admin_site
before.
The guide you linked is old and I was surprised to not find anything directly answering your question in the last year or so.
- Create a new Admin Site in your app's admin.py or in a convenient place.
- Create a function in the new AdminSite that augments the
get_urls()
function with your extra urls. - Make sure your project urls.py links to the newly created AdminSite.
The below works with Python 3.5.1 and Django 1.9.6.
my_app/admin.py
from django.contrib import admin
from django.contrib.admin import AdminSite
from django.http import HttpResponse
from my_app.models import SomeModel
class MyAdminSite(AdminSite):
def custom_view(self, request):
return HttpResponse("Test")
def get_urls(self):
from django.conf.urls import url
urls = super(MyAdminSite, self).get_urls()
urls += [
url(r'^custom_view/$', self.admin_view(self.custom_view))
]
return urls
admin_site = MyAdminSite()
@admin.register(SomeModel, site=admin_site)
class SomeModelAdmin(admin.ModelAdmin):
pass
my_project/urls.py
from django.conf.urls import url, include
from my_app.admin import admin_site
urlpatterns = [
url(r'^admin/', admin_site.urls),
...
]