Does argparse (python) support mutually exclusive groups of arguments?
The argparse
enhancement request referenced in @hpaulj's comment is still open after more than nine years, so I figured other people might benefit from the workaround I just discovered. Based on this comment in the enhancement request, I found I was able to add an option to two different mutually-exclusive groups using this syntax:
#!/usr/bin/env python
import argparse
import os
import sys
def parse_args():
parser = argparse.ArgumentParser(
formatter_class=argparse.ArgumentDefaultsHelpFormatter
)
parser.add_argument("-d", "--device", help="Path to UART device", default="./ttyS0")
mutex_group1 = parser.add_mutually_exclusive_group()
mutex_group2 = parser.add_mutually_exclusive_group()
mutex_group1.add_argument(
"-o",
"--output-file",
help="Name of output CSV file",
default="sensor_data_sent.csv",
)
input_file_action = mutex_group1.add_argument(
"-i", "--input-file", type=argparse.FileType("r"), help="Name of input CSV file"
)
# See: https://bugs.python.org/issue10984#msg219660
mutex_group2._group_actions.append(input_file_action)
mutex_group2.add_argument(
"-t",
"--time",
type=int,
help="How long to run, in seconds (-1 = loop forever)",
default=-1,
)
# Add missing ']' to usage message
usage = parser.format_usage()
usage = usage.replace('usage: ', '')
usage = usage.replace(']\n', ']]\n')
parser.usage = usage
return parser.parse_args()
if __name__ == "__main__":
args = parse_args()
print("Args parsed successfully...")
sys.exit(0)
This works well enough for my purposes:
$ ./fake_sensor.py -i input.csv -o output.csv
usage: fake_sensor.py [-h] [-d DEVICE] [-o OUTPUT_FILE | [-i INPUT_FILE | -t TIME]]
fake_sensor.py: error: argument -o/--output-file: not allowed with argument -i/--input-file
$ ./fake_sensor.py -i input.csv -t 30
usage: fake_sensor.py [-h] [-d DEVICE] [-o OUTPUT_FILE | [-i INPUT_FILE | -t TIME]]
fake_sensor.py: error: argument -t/--time: not allowed with argument -i/--input-file
$ ./fake_sensor.py -i input.csv
Args parsed successfully...
$ ./fake_sensor.py -o output.csv
Args parsed successfully...
$ ./fake_sensor.py -o output.csv -t 30
Args parsed successfully...
Accessing private members of argparse
is, of course, rather brittle, so I probably wouldn't use this approach in production code. Also, an astute reader may notice that the usage message is misleading, since it implies that -o
and -i
can be used together when they cannot(!) However, I'm using this script for testing only, so I'm not overly concerned. (Fixing the usage message 'for real' would, I think, require much more time than I can spare for this task, but please comment if you know a clever hack for this.)
Just stumbled on this problem myself. From my reading of the argparse docs, there doesn't seem to be a simple way to achieve that within argparse. I considered using parse_known_args, but that soon amounts to writing a special-purpose version of argparse ;-)
Perhaps a bug report is in order. In the meanwhile, if you're willing to make your user do a tiny bit extra typing, you can fake it with subgroups (like how git and svn's arguments work), e.g.
subparsers = parser.add_subparsers()
p_ab = subparsers.add_parser('ab')
p_ab.add_argument(...)
p_cd = subparsers.add_parser('cd')
p_cd.add_argument(...)
Not ideal, but at least it gives you the good from argparse without too much ugly hackery. I ended up doing away with the switches and just using the subparser operations with required subarguments.
EDIT: Never mind. Because argparse
makes the horrible choice of having to create an option when invoking group.add_argument
. That wouldn't be my design choice. If you're desperate for this feature, you can try doing it with ConflictsOptionParser:
# exclusivegroups.py
import conflictsparse
parser = conflictsparse.ConflictsOptionParser()
a_opt = parser.add_option('-a')
b_opt = parser.add_option('-b')
c_opt = parser.add_option('-c')
d_opt = parser.add_option('-d')
import itertools
compatible_opts1 = (a_opt, b_opt)
compatible_opts2 = (c_opt, d_opt)
exclusives = itertools.product(compatible_opts1, compatible_opts2)
for exclusive_grp in exclusives:
parser.register_conflict(exclusive_grp)
opts, args = parser.parse_args()
print "opts: ", opts
print "args: ", args
Thus when we invoke it, we can see we get the desired effect.
$ python exclusivegroups.py -a 1 -b 2
opts: {'a': '1', 'c': None, 'b': '2', 'd': None}
args: []
$ python exclusivegroups.py -c 3 -d 2
opts: {'a': None, 'c': '3', 'b': None, 'd': '2'}
args: []
$ python exclusivegroups.py -a 1 -b 2 -c 3
Usage: exclusivegroups.py [options]
exclusivegroups.py: error: -b, -c are incompatible options.
The warning message doesn't inform you that both '-a'
and '-b'
are incompatible with '-c'
, however a more appropriate error message could be crafted. Older, wrong answer below.
OLDER EDIT: [This edit is wrong, although wouldn't it be just a perfect world if argparse
worked this way?] My previous answer actually was incorrect, you should be able to do this with argparse
by specifying one group per mutually exclusive options. We can even use itertools
to generalize the process. And make it so we don't have to type out all the combinations explicitly:
import itertools
compatible_opts1 = ('-a', '-b')
compatible_opts2 = ('-c', '-d')
exclusives = itertools.product(compatible_opts1, compatible_opts2)
for exclusive_grp in exclusives:
group = parser.add_mutually_exclusive_group()
group.add_argument(exclusive_grp[0])
group.add_argument(exclusive_grp[1])