Escape sequences with "echo -e" in different shells

Because you used sh, not bash, then echo command in sh doesn't have option -e. From sh manpage:

echo [-n] args...
            Print the arguments on the standard output, separated by spaces.
            Unless the -n option is present, a newline is output following the
            arguments.

And it doesn't have \e, too:

        If any of the following sequences of characters is encountered
        during output, the sequence is not output.  Instead, the specified
        action is performed:

        \b      A backspace character is output.

        \c      Subsequent output is suppressed.  This is normally used at
                the end of the last argument to suppress the trailing new‐
                line that echo would otherwise output.

        \f      Output a form feed.

        \n      Output a newline character.

        \r      Output a carriage return.

        \t      Output a (horizontal) tab character.

        \v      Output a vertical tab.

        \0digits
                Output the character whose value is given by zero to three
                octal digits.  If there are zero digits, a nul character
                is output.

        \\      Output a backslash.

        All other backslash sequences elicit undefined behaviour.

-e is not POSIX (in fact, POSIX echo generally accepts no options, though it is allowed to support -n, see here), and /bin/sh on your system appears to be a POSIX shell. -e is an extension accepted in some shells, but you shouldn't rely on it, it's not portable. Ideally, use printf, or switch to using a shell which has echo -e.

Also see the caveats of \e in the comments below, which should be replaced with \033.

printf '\033[3;12r\033[3H'

Note that at any time and in almost any shell, you can figure out which "echo" will be called by typing type echo or which echo. It's usually a shell builtin. So it depends on which "echo" is installed and on which shell you're using.