Excluding certain files and directories when deleting files
As you already found out you can use the extglob
feature which is enabled with:
shopt -s extglob
This allows to exclude matches so that you can do things like:
rm 100/!([ab].txt) 101/!([cd].txt)
It's a good idea to test it with echo
first. This example will match anything inside 100/
which is not a.txt
or b.txt
and anything inside 101/
which is not c.txt
or d.txt
. If the same rules for 100/
apply to 102/
as well you can do e.g.:
10[02]/!([ab].txt) # or
{100,102}/!([ab].txt)
You could use find
for this. You can negate tests in find
with -not
or !
. This will exclude matches, rather than finding them.
You should be careful not to delete any of the parent directories of the files you want to keep, especially the current directory .
, so make sure you read the output thoroughly before deleting.
Based on your example you could do something like this from the data
directory.
find ! -path . ! -path ./100 ! -path ./101 ! -path "./100/[ab].txt" ! -path "./101/[cd].txt"
Add a ! -path ./path/to/dir
for any path you want to avoid deleting. You can use metacharacters like *
, but make sure you quote the expression if you do, eg "./path*dir"
, to prevent any unwanted expansions.
find
is recursive by default. Even if we don't find ./100
here, we will find all of its contents unless they match the pattern [ab].txt
. If you can't match all the names you want to keep, add another test:
! -path "./100/[ab].txt" ! -path ./100/foo
This won't find a.txt
or b.txt
or foo
, but it will find all other files.
When you are sure you see what you want, you can add -delete
to the end to delete the found files:
find ! -path . ! -path ./100 ! -path ./101 ! -path "./100/[ab].txt" ! -path "./101/[cd].txt" -delete