Explain the 0/1 Knapsack Problem to solve it using dynamic Programming code example

Example 1: 0-1 knapsack problem dynamic programming using single array

int dp[MAXW];
int solve()
{
    memset(dp, 0, sizeof(dp));
    for(int i =1; i <= N; i++) {
        for(int j = W; j >= 0; j--) {
            dp[j] = (w[i] > j) ? dp[j]: max(dp[j], dp[j-w[i]] + v[i]);
        }
    }
    return dp[W];
}

Example 2: knapsack problem using dynamic approach inc++

#include <iostream>
using namespace std;
int max(int x, int y) {
   return (x > y) ? x : y;
}
int knapSack(int W, int w[], int v[], int n) {
   int i, wt;
   int K[n + 1][W + 1];
   for (i = 0; i <= n; i++) {
      for (wt = 0; wt <= W; wt++) {
         if (i == 0 || wt == 0)
         K[i][wt] = 0;
         else if (w[i - 1] <= wt)
            K[i][wt] = max(v[i - 1] + K[i - 1][wt - w[i - 1]], K[i - 1][wt]);
         else
        K[i][wt] = K[i - 1][wt];
      }
   }
   return K[n][W];
}
int main() {
   cout << "Enter the number of items in a Knapsack:";
   int n, W;
   cin >> n;
   int v[n], w[n];
   for (int i = 0; i < n; i++) {
      cout << "Enter value and weight for item " << i << ":";
      cin >> v[i];
      cin >> w[i];
   }
   cout << "Enter the capacity of knapsack";
   cin >> W;
   cout << knapSack(W, w, v, n);
   return 0;
}