Extract lines from files with names begining with given letter

awk '$2 ~ /^L/' file

Tells awk to test the second field $2 using the regex ~ expression ^L and print the matching lines.

The regex matches the second field ($2) when it starts ^ with L

Building on @bu5hman's answer: With awk, you can easily pass the letter as a parameter:

awk -v letter="L" 'substr($2, 1, 1) == letter' file
# or with a constructed regex
awk -v letter="L" '$2 ~ "^" letter' file

That seems to be duplicated, but anyway, if it was understood, one may do it as follows:

First, save the list in a some nameslist.txt file, then:

sed -rn '/^[^\s]+\s+[F]/p' list.txt > result.txt, which should return following output in result.txt file:

60 FREDDIE 1201 +4 61 FINLAY 1200 -2