Fill an array with random numbers

This seems a little bit like homework. So I'll give you some hints. The good news is that you're almost there! You've done most of the hard work already!

• Think about a construct that can help you iterate over the array. Is there some sort of construct (a loop perhaps?) that you can use to iterate over each location in the array?
• Within this construct, for each iteration of the loop, you will assign the value returned by randomFill() to the current location of the array.

Note: Your array is double, but you are returning ints from randomFill. So there's something you need to fix there.

You can use IntStream ints() or DoubleStream doubles() available as of java 8 in Random class. something like this will work, depends if you want double or ints etc.

Random random = new Random();

int[] array = random.ints(100000, 10,100000).toArray();

you can print the array and you'll get 100000 random integers.

You need to add logic to assign random values to double[] array using randomFill method.

Change

 public static double[] list(){
    anArray = new double[10];   
    return anArray;
 }

To

 public static double[] list() {
    anArray = new double[10];
    for(int i=0;i<anArray.length;i++)
    {
        anArray[i] = randomFill();
    }
    return anArray;
}

Then you can call methods, including list() and print() in main method to generate random double values and print the double[] array in console.

 public static void main(String args[]) {

list();
print();
 }

One result is as follows:

-2.89783865E8 
1.605018025E9 
-1.55668528E9 
-1.589135498E9 
-6.33159518E8 
-1.038278095E9 
-4.2632203E8 
1.310182951E9 
1.350639892E9 
6.7543543E7