Filtering an array of objects that contain arrays
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays {tags: [], weights: []}:
const arr = [{tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf'},{tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd'},{tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh'},{tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'}];
const obj = arr.reduce((a, {tags, weight}) => {
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
}, {tags: [], weights: []});
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper { max-height: 100% !important; top: 0; }One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
{
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
},
{
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
},
{
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
},
{
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
}
];
let res = arr.reduce((acc, {tags, weight}) =>
{
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
}, {tags: new Set(), weights: new Set()});
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}