Filtering Table rows using Jquery

There's no need to build an array. You can address the DOM directly.

Try :

rows.hide();
$.each(data, function(i, v){
    rows.filter(":contains('" + v + "')").show();
});

DEMO

EDIT

To discover the qualifying rows without displaying them immediately, then pass them to a function :

$("#searchInput").keyup(function() {
    var rows = $("#fbody").find("tr").hide();
    var data = this.value.split(" ");
    var _rows = $();//an empty jQuery collection
    $.each(data, function(i, v) {
        _rows.add(rows.filter(":contains('" + v + "')");
    });
    myFunction(_rows);
});

UPDATED DEMO

Have a look at this jsfiddle.

The idea is to filter rows with function which will loop through words.

jo.filter(function (i, v) {
    var $t = $(this);
    for (var d = 0; d < data.length; ++d) {
        if ($t.is(":contains('" + data[d] + "')")) {
            return true;
        }
    }
    return false;
})
//show the rows that match.
.show();

EDIT: Note that case insensitive filtering cannot be achieved using :contains() selector but luckily there's text() function so filter string should be uppercased and condition changed to if ($t.text().toUpperCase().indexOf(data[d]) > -1). Look at this jsfiddle.