Find angle between hour and minute hands in an analog clock

It turns out that Wikipedia does have the best answer:

// h = 1..12, m = 0..59
static double angle(int h, int m) {
    double hAngle = 0.5D * (h * 60 + m);
    double mAngle = 6 * m;
    double angle = Math.abs(hAngle - mAngle);
    angle = Math.min(angle, 360 - angle);
    return angle;
}

Basically:

• The hour hand moves at the rate of 0.5 degrees per minute
• The minute hand moves at the rate of of 6 degrees per minute

Problem solved.

---

And precision isn't a concern because the fractional part is either .0 or .5, and in the range of 0..360, all of these values are exactly representable in double.

For finding the angle between the hands of a clock is ,

30 * [HRS - (MIN/5)] + (MIN/2)