Finding solutions to $2^x+17=y^2$
The only solutions are $x = 3, 5, 6, 9$. This is proved on pp. 148-152 of
Tzanakis, N. (1983), On the diophantine equation $y^2-D = 2^k$, J. Number Theory 17, 144-64.
The only solutions are $x = 3, 5, 6, 9$. This is proved on pp. 148-152 of
Tzanakis, N. (1983), On the diophantine equation $y^2-D = 2^k$, J. Number Theory 17, 144-64.