Firebase, variable as key name

For the latest version of Firebase, use brackets around the variable name:

firebase.database().ref("pathName").set({[variable] : 'MoreStuff'});

Using the other method of setting the index of the variable to the value will create an additional layer in the database structure.

Yes. The code is not working as expected because you are using object literal notation, which is the reason the it keeps the variable name as key, because that is how the notation works.

Solution

foo = {}; 
foo[variable] = 'more stuff'; 
fb.set(foo);