/* fun will take an array of ints and sum two consecutive ints * and put them in a new array, until there are not two consecutive ints. * Hint: the length of the new array will be one less than the array given. */ code example

Example 1: create a function that checks the values of the indexes in two arrays and keep a score

const triplets = (arr1,arr2) => {
  let score1 = 0;
  let score2 = 0;
  let resultArr = [0,0]
  for (let i = 0; i < arr1.length; i++){
    if(arr1[i] === arr2[i]) {
      resultArr[0] = score1
      resultArr[1] = score2
    } else if (arr1[i] > arr2[i]) {
      score1++
      resultArr[0] = score1
    } else if (arr1[i] < arr2[i]) {
      score2++
      resultArr[1] = score2
    }
  }
  return resultArr
}

Example 2: find pair in unsorted array which gives sum x

// C++ program to check if given array 
// has 2 elements whose sum is equal 
// to the given value 
  
#include <bits/stdc++.h> 
using namespace std; 
  
// Function to check if array has 2 elements 
// whose sum is equal to the given value 
bool hasArrayTwoCandidates(int A[], int arr_size, 
                           int sum) 
{ 
    int l, r; 
  
    /* Sort the elements */
    sort(A, A + arr_size); 
  
    /* Now look for the two candidates in  
       the sorted array*/
    l = 0; 
    r = arr_size - 1; 
    while (l < r) { 
        if (A[l] + A[r] == sum) 
            return 1; 
        else if (A[l] + A[r] < sum) 
            l++; 
        else // A[i] + A[j] > sum 
            r--; 
    } 
    return 0; 
} 
  
/* Driver program to test above function */
int main() 
{ 
    int A[] = { 1, 4, 45, 6, 10, -8 }; 
    int n = 16; 
    int arr_size = sizeof(A) / sizeof(A[0]); 
  
    // Function calling 
    if (hasArrayTwoCandidates(A, arr_size, n)) 
        cout << "Array has two elements with given sum"; 
    else
        cout << "Array doesn't have two elements with given sum"; 
  
    return 0; 
}