Generate random 6 digit number
You want to have a string:
Random r = new Random();
var x = r.Next(0, 1000000);
string s = x.ToString("000000");
For example,
x = "2124"
s = "002124"
private static string _numbers = "0123456789";
Random random = new Random();
private void DoWork()
{
StringBuilder builder = new StringBuilder(6);
string numberAsString = "";
int numberAsNumber = 0;
for (var i = 0; i < 6; i++)
{
builder.Append(_numbers[random.Next(0, _numbers.Length)]);
}
numberAsString = builder.ToString();
numberAsNumber = int.Parse(numberAsString);
}
As stated in a comment, a "six digit number" is a string. Here's how you generate a number from 0-999999, then format it like "000482":
Random r = new Random();
int randNum = r.Next(1000000);
string sixDigitNumber = randNum.ToString("D6");
If you want a string to lead with zeroes, try this. You cannot get an int like 001.
Random generator = new Random();
String r = generator.Next(0, 1000000).ToString("D6");