Generating random text strings of a given pattern
See an example - Recipe 59873: Random Password Generation .
Building on the recipe, here is a solution to your question :
from random import choice
import string
def GenPasswd2(length=8, chars=string.letters + string.digits):
return ''.join([choice(chars) for i in range(length)])
>>> GenPasswd2(8,string.digits) + GenPasswd2(15,string.ascii_letters)
'28605495YHlCJfMKpRPGyAw'
>>>
#!/usr/bin/python
import random
import string
digits = "".join( [random.choice(string.digits) for i in xrange(8)] )
chars = "".join( [random.choice(string.letters) for i in xrange(15)] )
print digits + chars
EDIT: liked the idea of using random.choice better than randint() so I've updated the code to reflect that.
Note: this assumes lowercase and uppercase characters are desired. If lowercase only then change the second list comprehension to read:
chars = "".join( [random.choice(string.letters[:26]) for i in xrange(15)] )
Obviously for uppercase only you can just flip that around so the slice is [26:] instead of the other way around.