get every n3 array code example

Example: n/3 number appears in array elements

// CPP program to find if any element appears 
// more than n/3. 
#include <bits/stdc++.h> 
using namespace std; 

int appearsNBy3(int arr[], int n) 
{ 
	int count1 = 0, count2 = 0; 
	int first=INT_MAX , second=INT_MAX ; 

	for (int i = 0; i < n; i++) { 

		// if this element is previously seen, 
		// increment count1. 
		if (first == arr[i]) 
			count1++; 

		// if this element is previously seen, 
		// increment count2. 
		else if (second == arr[i]) 
			count2++; 
	
		else if (count1 == 0) { 
			count1++; 
			first = arr[i]; 
		} 

		else if (count2 == 0) { 
			count2++; 
			second = arr[i]; 
		} 

		// if current element is different from 
		// both the previously seen variables, 
		// decrement both the counts. 
		else { 
			count1--; 
			count2--; 
		} 
	} 

	count1 = 0; 
	count2 = 0; 

	// Again traverse the array and find the 
	// actual counts. 
	for (int i = 0; i < n; i++) { 
		if (arr[i] == first) 
			count1++; 

		else if (arr[i] == second) 
			count2++; 
	} 

	if (count1 > n / 3) 
		return first; 

	if (count2 > n / 3) 
		return second; 

	return -1; 
} 

int main() 
{ 
	int arr[] = { 1, 2, 3, 1, 1 }; 
	int n = sizeof(arr) / sizeof(arr[0]); 
	cout << appearsNBy3(arr, n) << endl; 
	return 0; 
}