Get filename of file which ran PHP include

Late answer, but ...

I check the running parent filename by using:

$_SERVER["SCRIPT_NAME"] // or 
$_SERVER["REQUEST_URI"] // (with query string)

An easy way is to assign a variable in the parent file (before the inclue), then reference that variable in the included file.

Parent File:

$myvar_not_replicated = __FILE__; // Make sure nothing else is going to overwrite
include 'other_file.php';

Included File:

if (isset($myvar_not_replicated)) echo "{$myvar_not_replicated} included me";
else echo "Unknown file included me";

---

You could also mess around with get_included_files() or debug_backtrace() and find the event when and where the file got included, but that can get a little messy and complicated.

$fileList = get_included_files();
$topMost = $fileList[0];
if ($topMost == __FILE__) echo 'no parents';
else echo "parent is $topMost";

I think this should give the right result when there's a single parent.

By that I mean the situation where the parent is not a required or an included file itself.

You could use debug_backtrace() directly with no additional changes from within the included file:

$including_filename = pathinfo(debug_backtrace()[0]['file'])['basename'];

This will give you the name of the file that's including you.

To see everything you have access to from within the included file, run this from within it:

print_r(debug_backtrace());

You will get something like:

Array
(
    [0] => Array
        (
            [file] => /var/folder/folder/folder/file.php
            [line] => 554
            [function] => include
        )

)