Get item in sub array and put back to main array

Instead of join() use Array.prototype.flat() on the returned result of map():

var array_demo = [
    ['1st', '1595', '8886'],
    ['2nd', '1112']
]
array_demo = array_demo.map(function(i) {
    return i.slice(1);
}).flat();
console.log(array_demo);

In one liner using Arrow function(=>):

var array_demo = [
    ['1st', '1595', '8886'],
    ['2nd', '1112']
]
array_demo = array_demo.map(i => i.slice(1)).flat();
console.log(array_demo);

You can use Array.prototype.flat followed by a Array.prototype.filter to get rid of the non-numeric data in your subarrays:

var array_demo = [
    ['1st', '1595', '8886'],
    ['2nd', '1112']
];

const res = array_demo.flat().filter(n=> !isNaN(n));
console.log(res);

We could do it using Array.prototype.reduce also, if your objective is to remove only the object at the 0th index:

var array_demo = [
    ['1st', '1595', '8886'],
    ['2nd', '1112']
];

const res = array_demo.reduce((r, [_, ...e]) => { r.push(...e); return r}, []);
console.log(res);

You could destructure the array and take the rest without the first element and flatten this array using Array.flatMap.

var array = [['1st', '1595', '8886'], ['2nd', '1112']],
    result = array.flatMap(([_, ...a]) => a);

console.log(result);

Alternatively Array.slice() works as well.

var array = [['1st', '1595', '8886'], ['2nd', '1112']],
    result = array.flatMap(a => a.slice(1));

console.log(result);