Get path of current script when executed through a symlink

Try this as a general purpose solution:

DIR="$(cd "$(dirname "$0")" && pwd)"

In the specific case of following symlinks, you could also do this:

DIR="$(dirname "$(readlink -f "$0")")"

one line:

cd $(dirname $([ -L $0 ] && readlink -f $0 || echo $0))

readlink -f doesn't work for me, I've this mistake:

readlink: illegal option -- f
usage: readlink [-n] [file ...]

But this works fine:

DIR="$(dirname "$(readlink "$0")")"
echo $DIR