Getting only 1 decimal place
Are you trying to represent it with only one digit:
print("{:.1f}".format(number)) # Python3
print "%.1f" % number # Python2
or actually round off the other decimal places?
round(number,1)
or even round strictly down?
math.floor(number*10)/10
>>> "{:.1f}".format(45.34531)
'45.3'
Or use the builtin round:
>>> round(45.34531, 1)
45.299999999999997
round(number, 1)