Given a number N, you have to perform only two types of operations on the number:- 1) If N is odd increase it by 1 2) If N is even divide it by 2 Your task is to find the number of operations it takes to make N equal to 1. sanfoundary code example

Example: minimum-number-of-steps-to-reduce-number-to-1

#minimum-number-of-steps-to-reduce-number-to-1
def stepCount(n):
    count = 0
    while n > 1:
        if n % 2 == 0:             # bitmask: *0
            n = n // 2
        elif n == 3 or n % 4 == 1: # bitmask: 01
            n = n - 1
        else:                      # bitmask: 11
            n = n + 1
        count += 1
    return count