Go / golang time.Now().UnixNano() convert to milliseconds?

Just divide it:

func makeTimestamp() int64 {
    return time.Now().UnixNano() / int64(time.Millisecond)
}

Here is an example that you can compile and run to see the output

package main

import (
    "time"
    "fmt"
)

func main() {
    a := makeTimestamp()

    fmt.Printf("%d \n", a)
}

func makeTimestamp() int64 {
    return time.Now().UnixNano() / int64(time.Millisecond)
}

As @Jono points out in @OneOfOne's answer, the correct answer should take into account the duration of a nanosecond. Eg:

func makeTimestamp() int64 {
    return time.Now().UnixNano() / (int64(time.Millisecond)/int64(time.Nanosecond))
}

OneOfOne's answer works because time.Nanosecond happens to be 1, and dividing by 1 has no effect. I don't know enough about go to know how likely this is to change in the future, but for the strictly correct answer I would use this function, not OneOfOne's answer. I doubt there is any performance disadvantage as the compiler should be able to optimize this perfectly well.

See https://en.wikipedia.org/wiki/Dimensional_analysis

Another way of looking at this is that both time.Now().UnixNano() and time.Millisecond use the same units (Nanoseconds). As long as that is true, OneOfOne's answer should work perfectly well.

Keep it simple.

func NowAsUnixMilli() int64 {
    return time.Now().UnixNano() / 1e6
}