Groovy: Generate random string from given character set
For SoupUI users:
def generator = { String alphabet, int n ->
new Random().with {
(1..n).collect { alphabet[ nextInt( alphabet.length() ) ] }.join()
}
}
randomValue = generator( (('A'..'Z')+('0'..'9')+('a'..'z')).join(), 15 )
testRunner.getTestCase().setPropertyValue("randomNumber", randomValue);
Here is a single line command/statement to generate random text string
print new Random().with {(1..9).collect {(('a'..'z')).join()[ nextInt((('a'..'z')).join().length())]}.join()}
or
def randText = print new Random().with {(1..9).collect {(('a'..'z')).join()[ nextInt((('a'..'z')).join().length())]}.join()}
import org.apache.commons.lang.RandomStringUtils
String charset = (('A'..'Z') + ('0'..'9')).join()
Integer length = 9
String randomString = RandomStringUtils.random(length, charset.toCharArray())
The imported class RandomStringUtils
is already on the Grails classpath, so you shouldn't need to add anything to the classpath if you're writing a Grails app.
Update
If you only want alphanumeric characters to be included in the String you can replace the above with
String randomString = org.apache.commons.lang.RandomStringUtils.random(9, true, true)
If you don't want to use apache commons, or aren't using Grails, an alternative is:
def generator = { String alphabet, int n ->
new Random().with {
(1..n).collect { alphabet[ nextInt( alphabet.length() ) ] }.join()
}
}
generator( (('A'..'Z')+('0'..'9')).join(), 9 )
but again, you'll need to make your alphabet
yourself... I don't know of anything which can parse a regular expression and extract out an alphabet of passing characters...