Hibernate and no PK

Roger's self-answer is correct. To elaborate a bit on what is meant (I wasn't clear on it at first and figured this would help):

Say you have you have a table Foo as such:

TABLE Foo (
bar varchar(20),
bat varchar(20)
)

Normally, you can write a class w/Annotations to work with this table:

// Technically, for this example, the @Table and @Column annotations 
// are not needed, but don't hurt. Use them if your column names 
// are different than the variable names.

@Entity
@Table(name = "FOO")
class Foo {

  private String bar;
  private String bat;


  @Column(name = "bar")
  public String getBar() {
   return bar;    
  }

  public void setBar(String bar) {
   this.bar = bar;    
  }

  @Column(name = "bat")
  public String getBat() {
   return bat;    
  }

  public void setBat(String bat) {
   this.bat = bat;    
  }

}

.. But, darn. This table has nothing we can use as an id, and it's a legacy database that we use for [insert vital business function]. I don't think they'll let me start modifying tables in order for me to use hibernate.

You can, instead, split the object up into a hibernate-workable structure which allows the entire row to be used as the key. (Naturally, this assumes that the row is unique.)

Split the Foo object into two thusly:

@Entity
@Table(name = "FOO")
class Foo {

  @Id
  private FooKey id;

  public void setId(FooKey id) {
    this.id = id;
  }

  public void getId() {
    return id;
  }
}

and

@Embeddable
class FooKey implements Serializable {
  private String bar;
  private String bat;

  @Column(name = "bar")
  public String getBar() {
   return bar;    
  }

  public void setBar(String bar) {
   this.bar = bar;    
  }

  @Column(name = "bat")
  public String getBat() {
   return bat;    
  }

  public void setBat(String bat) {
   this.bat = bat;    
  }

}

.. And that should be it. Hibernate will use the Embeddable key for its required identity and you can make a call as normal:

Query fooQuery = getSession().createQuery("from Foo");

Hope this helps first-timers with getting this working.

i found that this trick works:

<id column="ROWID" type="string" />

Use following code; Hibernate doesn't have its own logic to distinguish duplicate records

Let me know if there are any issues with this approach

@Entity @IdClass(Foo.class)
class Foo implements Serializable {
  @Id private String bar;
  @Id private String bat;

  public String getBar() {
   return bar;    
  }

  public void setBar(String bar) {
   this.bar = bar;
  }


  public String getBat() {
   return bat;    
  }

  public void setBat(String bat) {
   this.bat = bat;    
  }
}

I found that its not possible to do so. So bad luck for those working with legacy systems.

If you reverse engineer (create JPA annotated entities from existing JDBC connection) the table will create two Java classes, one Entity and with one field; id, and one embeddable id containing all the columns from your relation.