How can I assign a Variant to a Variant in VBA?
Dim v As Variant
For Each v In Array(SomeMethod())
Exit For 'Needed for v to retain it's value
Next v
'Use v here - v is now holding a value or a reference
It appears that I wasn't the only one with this issue.
The solution was given to me here.
In short:
Public Declare Sub VariantCopy Lib "oleaut32.dll" (ByRef pvargDest As Variant, ByRef pvargSrc As Variant)
Sub Main()
Dim v as Variant
VariantCopy v, SomeMethod()
end sub
It seems this is similar to the LetSet()
function described in the answer, but I figured this'd be useful anyway.
In VBA, the only way to assign a Variant to a variable where you don't know if it is an object or a primitive, is by passing it as a parameter.
If you cannot refactor your code so that the v
is passed as a parameter to a Sub, Function or Let Property (despite the Let
this also works on objects), you could always declare v
in module scope and have a dedicated Sub solely for the purpose of save-assigning that variable:
Private v As Variant
Private Sub SetV(ByVal var As Variant)
If IsObject(var) Then
Set v = var
Else
v = var
End If
End Sub
with somewhere else calling SetV SomeMethod()
.
Not pretty, but it's the only way without calling SomeMethod()
twice or touching its inner workings.
Edit
Ok, I mulled over this and I think I found a better solution that comes closer to what you had in mind:
Public Sub LetSet(ByRef variable As Variant, ByVal value As Variant)
If IsObject(value) Then
Set variable = value
Else
variable = value
End If
End Sub
[...] I guess there just is no LetSet v = ... statement in VBA
Now there is: LetSet v, SomeMethod()
You don't have a return value that you need to Let
or Set
to a variable depending of its type, instead you pass the variable that should hold the return value as first parameter by reference so that the Sub can change its value.
You could use error trapping to reduce the expected number of method calls. First try to set. If that succeeds -- no problem. Otherwise, just assign:
Public counter As Long
Function Ambiguous(b As Boolean) As Variant
counter = counter + 1
If b Then
Set Ambiguous = ActiveSheet
Else
Ambiguous = 1
End If
End Function
Sub test()
Dim v As Variant
Dim i As Long, b As Boolean
Randomize
counter = 0
For i = 1 To 100
b = Rnd() < 0.5
On Error Resume Next
Set v = Ambiguous(b)
If Err.Number > 0 Then
Err.Clear
v = Ambiguous(b)
End If
On Error GoTo 0
Next i
Debug.Print counter / 100
End Sub
When I ran the code, the first time I got 1.55, which is less than the 2.00 you would get if you repeated the experiment but with the error-handling approach replaced by the naïve if-then-else
approach you discussed in your question.
Note that the more often the function returns an object, the less function calls on average. If it almost always returns an object (e.g. that is what it is supposed to return but returns a string describing an error condition in certain cases) then this way of doing things will approach 1 call per setting/ assigning the variable. On the other hand -- if it almost always returns a primitive value then you will approach 2 calls per assignment -- in which case perhaps you should refactor your code.