How can I enter a password using Perl and replace the characters with '*'?
In the past I have used IO::Prompt for this.
use IO::Prompt;
my $password = prompt('Password:', -e => '*');
print "$password\n";
If you don't want use any packages... Only for UNIX
system('stty','-echo');
chop($password=<STDIN>);
system('stty','echo');
You can play with Term::ReadKey. Here is a very simple example, with some detection for backspace and delete key. I've tested it on Mac OS X 10.5 but according to the ReadKey manual it should work under Windows. The manual indicates that under Windows using non-blocking reads (ReadKey(-1)
) will fail. That's why I'm using ReadKey(0) who's basically getc
(more on getc in the libc manual).
#!/usr/bin/perl
use strict;
use warnings;
use Term::ReadKey;
my $key = 0;
my $password = "";
print "\nPlease input your password: ";
# Start reading the keys
ReadMode(4); #Disable the control keys
while(ord($key = ReadKey(0)) != 10)
# This will continue until the Enter key is pressed (decimal value of 10)
{
# For all value of ord($key) see http://www.asciitable.com/
if(ord($key) == 127 || ord($key) == 8) {
# DEL/Backspace was pressed
#1. Remove the last char from the password
chop($password);
#2 move the cursor back by one, print a blank character, move the cursor back by one
print "\b \b";
} elsif(ord($key) < 32) {
# Do nothing with these control characters
} else {
$password = $password.$key;
print "*(".ord($key).")";
}
}
ReadMode(0); #Reset the terminal once we are done
print "\n\nYour super secret password is: $password\n";