How can I get a unique array based on object property using underscore

If you want to check all the properties then lodash 4 comes with _.uniqWith(sourceArray, _.isEqual)

Use the uniq function

var destArray = _.uniq(sourceArray, function(x){
    return x.name;
});

or single-line version

var destArray = _.uniq(sourceArray, x => x.name);

From the docs:

Produces a duplicate-free version of the array, using === to test object equality. If you know in advance that the array is sorted, passing true for isSorted will run a much faster algorithm. If you want to compute unique items based on a transformation, pass an iterator function.

In the above example, the function uses the objects name in order to determine uniqueness.

If you prefer to do things yourself without Lodash, and without getting verbose, try this uniq filter with optional uniq by property:

const uniqFilterAccordingToProp = function (prop) {
    if (prop)
        return (ele, i, arr) => arr.map(ele => ele[prop]).indexOf(ele[prop]) === i
    else
        return (ele, i, arr) => arr.indexOf(ele) === i
}

Then, use it like this:

const obj = [ { id: 1, name: 'bob' }, { id: 1, name: 'bill' }, { id: 1, name: 'bill' } ]
obj.filter(uniqFilterAccordingToProp('abc'))

Or for plain arrays, just omit the parameter, while remembering to invoke:

[1,1,2].filter(uniqFilterAccordingToProp())