How can I get indexPath.row in cell.swift
Easy.. You can do like this inside button action:
let section = 0
let row = sender.tag
let indexPath = IndexPath(row: row, section: section)
let cell: myTableCell = self.feedTableView.cellForRow(at: indexPath) as! myTableCell
And afterwards in cellForRowAtIndexPath
:
// add the row as the tag
cell.button.tag = indexPath.row
I have created a UIResponder
extension with a recursive method that you can use in any UIView
(which inherits from UIResponder
) to find a parent view of a specific type.
import UIKit
extension UIResponder {
/**
* Returns the next responder in the responder chain cast to the given type, or
* if nil, recurses the chain until the next responder is nil or castable.
*/
func next<U: UIResponder>(of type: U.Type = U.self) -> U? {
return self.next.flatMap({ $0 as? U ?? $0.next() })
}
}
Using this, we can extend UITableViewCell
with some convenient read-only computed properties for the table view and index path of the cell.
extension UITableViewCell {
var tableView: UITableView? {
return self.next(of: UITableView.self)
}
var indexPath: IndexPath? {
return self.tableView?.indexPath(for: self)
}
}
Here is how you could use it in your example:
@IBAction func likeBtnTapped(_ sender: AnyObject) {
//declare title of button
let title = sender.title(for: UIControlState())
//I want get indexPath.row in here!
self.indexPath.flatMap { print($0) }
}
Swift 4+
Try this inside your cell.
func getIndexPath() -> IndexPath? {
guard let superView = self.superview as? UITableView else {
print("superview is not a UITableView - getIndexPath")
return nil
}
indexPath = superView.indexPath(for: self)
return indexPath
}