How can I get real path for file in my WebContent folder?

getServletContext().getRealPath("") - This way will not work if content is being made available from a .war archive. getServletContext() will be null.

In this case we can use another way to get real path. This is example of getting a path to a properties file C:/Program Files/Tomcat 6/webapps/myapp/WEB-INF/classes/somefile.properties:

// URL returned "/C:/Program%20Files/Tomcat%206.0/webapps/myapp/WEB-INF/classes/"
URL r = this.getClass().getResource("/");

// path decoded "/C:/Program Files/Tomcat 6.0/webapps/myapp/WEB-INF/classes/"
String decoded = URLDecoder.decode(r.getFile(), "UTF-8");

if (decoded.startsWith("/")) {
    // path "C:/Program Files/Tomcat 6.0/webapps/myapp/WEB-INF/classes/"
    decoded = decoded.replaceFirst("/", "");
}
File f = new File(decoded, "somefile.properties");

If you need this in a servlet then use getServletContext().getRealPath("/filepathInContext")!

you must tell java to change the path from your pc into your java project so if you use spring use :

@Autowired
ServletContext c;

String UPLOAD_FOLDEdR=c.getRealPath("/images"); 

but if you use servlets just use

String UPLOAD_FOLDEdR = ServletContext.getRealPath("/images");  

so the path will be /webapp/images/ :)