How can I get the number of trainable parameters of a model in Keras?

from keras import backend as K

trainable_count = int(
    np.sum([K.count_params(p) for p in set(model.trainable_weights)]))
non_trainable_count = int(
    np.sum([K.count_params(p) for p in set(model.non_trainable_weights)]))

print('Total params: {:,}'.format(trainable_count + non_trainable_count))
print('Trainable params: {:,}'.format(trainable_count))
print('Non-trainable params: {:,}'.format(non_trainable_count))

The above snippet can be discovered in the end of layer_utils.print_summary() definition, which summary() is calling.

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Edit: more recent version of Keras has a helper function count_params() for this purpose:

from keras.utils.layer_utils import count_params

trainable_count = count_params(model.trainable_weights)
non_trainable_count = count_params(model.non_trainable_weights)

For tensorflow.keras this works for me. Its from the tensorflow github code for the function print_layer_summary_with_connections() in layer_utils.py

import numpy as np
from tensorflow.python.util import object_identity

def count_params(weights):
    return int(sum(np.prod(p.shape.as_list())
      for p in object_identity.ObjectIdentitySet(weights)))

if hasattr(model, '_collected_trainable_weights'):
    trainable_count = count_params(model._collected_trainable_weights)
else:
    trainable_count = count_params(model.trainable_weights)

print (trainable_count)

For TensorFlow 2.0:

import tensorflow.keras.backend as K

trainable_count = np.sum([K.count_params(w) for w in model.trainable_weights])
non_trainable_count = np.sum([K.count_params(w) for w in model.non_trainable_weights])

print('Total params: {:,}'.format(trainable_count + non_trainable_count))
print('Trainable params: {:,}'.format(trainable_count))
print('Non-trainable params: {:,}'.format(non_trainable_count))