How can I replace all occurrences of a substring using regex?
re.sub(r'\bfoo\b', 'bar', s)
Here, the \b
defines the word boundaries - positions between a word character (\w
) and a non-word character - exactly what you have matching for foo
inside the sdfjoiweng%@$foo$fsoifjoi
string. Works for me:
In [1]: import re
In [2]: s = 'sdfjoiweng%@$foo$fsoifjoi'
In [3]: re.sub(r'\bfoo\b', 'bar', s)
Out[3]: 'sdfjoiweng%@$bar$fsoifjoi'
You can use replace function directly instead of using regex.
>>> s = 'sdfjoiweng%@$foo$fsoifjoifoo'
>>>
>>> s.replace("foo","bar")
'sdfjoiweng%@$bar$fsoifjoibar'
>>>
>>>
You can replace it directly:
>>> import re
>>> s = 'sdfjoiweng%@$foo$fsoifjoi'
>>> print(re.sub('foo','bar',s))
sdfjoiweng%@$bar$fsoifjoi
It will also work for more occurrences of foo
like below:
>>> s = 'sdfjoiweng%@$foo$fsoifoojoi'
>>> print(re.sub('foo','bar',s))
sdfjoiweng%@$bar$fsoibarjoi
If you want to replace only the 1st occurrence of foo
and not all the foo
occurrences in the string then alecxe's answer does exactly that.