How do I chain commands on the console?

Use && operator,

cmd1 && cmd2 && cmd3

---

In shellscripting, && and || operators are modelled after optimized implementation of logical operators in C. && means AND operator, and || means OR. Unix is tightly related to C, and in C, the second operand of logical operators isn't evaluated if the result is already known from the first operand. E.g. "false && x" is false for any x, so there is no need to evaluate x (especially if x is a function call); similarly for "true || x". This is also called short-circuiting semantics.

And in Unix, it is traditional to interpret commands' return values as "successful completion" truth values: exit code 0 means true (success), nonzero means false (failure). So, when the first command in cmd1 && cmd2 returns "false" (nonzero exit status, which indicates failure), the compound command's status is known: failure. So overall interpretation of cmd1 && cmd2 may be: "execute cmd1, AND THEN, if it didn't fail, cmd2". Which is what you basically want in your question.

Similarly with OR: cmd1 || cmd2 can be interpreted as "execute cmd1, OR IF it fails, cmd2".

---

Protip: for longer chains of &&, consider putting set -e in your script. It basically changes the semicolon ; into &&, with a couple of special cases.

"Chaining Commands an grouping them"

ping 192.168.0.1 || { echo "ping not successful"; exit 1; }

pings, only if not successful, executes the chained group of commands in brackets.

Attention:

The list has to be terminated with a ";".

There must be blank spaces between brackets and the grouped commands!

Simply with the && operator. For instance:

cmd1 && cmd2 && cmd3

If one of the commands fails (returns an exit value other than 0), the other commands won't run.