How do I create a custom Error in JavaScript?

All of the above answers are terrible awful - really. Even the one with 107 ups! The real answer is here guys:

Inheriting from the Error object - where is the message property?

TL;DR:

A. The reason message isn't being set is that Error is a function that returns a new Error object and does not manipulate this in any way.

B. The way to do this right is to return the result of the apply from the constructor, as well as setting the prototype in the usual complicated javascripty way:

function MyError() {
    var temp = Error.apply(this, arguments);
    temp.name = this.name = 'MyError';
    this.message = temp.message;
    if(Object.defineProperty) {
        // getter for more optimizy goodness
        /*this.stack = */Object.defineProperty(this, 'stack', { 
            get: function() {
                return temp.stack
            },
            configurable: true // so you can change it if you want
        })
    } else {
        this.stack = temp.stack
    }
}
//inherit prototype using ECMAScript 5 (IE 9+)
MyError.prototype = Object.create(Error.prototype, {
    constructor: {
        value: MyError,
        writable: true,
        configurable: true
    }
});

var myError = new MyError("message");
console.log("The message is: '" + myError.message + "'"); // The message is: 'message'
console.log(myError instanceof Error); // true
console.log(myError instanceof MyError); // true
console.log(myError.toString()); // MyError: message
console.log(myError.stack); // MyError: message \n 
// <stack trace ...>


 
//for EMCAScript 4 or ealier (IE 8 or ealier), inherit prototype this way instead of above code:
/*
var IntermediateInheritor = function() {};
IntermediateInheritor.prototype = Error.prototype;
MyError.prototype = new IntermediateInheritor();
*/

You could probably do some trickery to enumerate through all the non-enumerable properties of the tmp Error to set them rather than explicitly setting only stack and message, but the trickery isn't supported in ie<9

In ES2015, you can use class to do this cleanly:

class NotImplemented extends Error {
  constructor(message = "", ...args) {
    super(message, ...args);
    this.message = message + " has not yet been implemented.";
  }
}

This does not modify the global Error prototype, allows you to customize message, name, and other attributes, and properly captures the stack. It's also pretty readable.

Of course, you may need to use a tool like babel if your code will be running on older browsers.

Update your code to assign your prototype to the Error.prototype and the instanceof and your asserts work.

function NotImplementedError(message = "") {
    this.name = "NotImplementedError";
    this.message = message;
}
NotImplementedError.prototype = Error.prototype;

However, I would just throw your own object and just check the name property.

throw {name : "NotImplementedError", message : "too lazy to implement"}; 

Edit based on comments

After looking at the comments and trying to remember why I would assign prototype to Error.prototype instead of new Error() like Nicholas Zakas did in his article, I created a jsFiddle with the code below:

function NotImplementedError(message = "") {
  this.name = "NotImplementedError";
  this.message = message;
}
NotImplementedError.prototype = Error.prototype;

function NotImplementedError2(message = "") {
  this.message = message;
}
NotImplementedError2.prototype = new Error();

try {
  var e = new NotImplementedError("NotImplementedError message");
  throw e;
} catch (ex1) {
  console.log(ex1.stack);
  console.log("ex1 instanceof NotImplementedError = " + (ex1 instanceof NotImplementedError));
  console.log("ex1 instanceof Error = " + (ex1 instanceof Error));
  console.log("ex1.name = " + ex1.name);
  console.log("ex1.message = " + ex1.message);
}

try {
  var e = new NotImplementedError2("NotImplementedError2 message");
  throw e;
} catch (ex1) {
  console.log(ex1.stack);
  console.log("ex1 instanceof NotImplementedError2 = " + (ex1 instanceof NotImplementedError2));
  console.log("ex1 instanceof Error = " + (ex1 instanceof Error));
  console.log("ex1.name = " + ex1.name);
  console.log("ex1.message = " + ex1.message);
}

The console output was this.

undefined
ex1 instanceof NotImplementedError = true
ex1 instanceof Error = true
ex1.name = NotImplementedError
ex1.message = NotImplementedError message
Error
    at window.onload (http://fiddle.jshell.net/MwMEJ/show/:29:34)
ex1 instanceof NotImplementedError2 = true
ex1 instanceof Error = true
ex1.name = Error
ex1.message = NotImplementedError2 message

This confirmes the "problem" I ran into was the stack property of the error was the line number where new Error() was created, and not where the throw e occurred. However, that may be better that having the side effect of a NotImplementedError.prototype.name = "NotImplementedError" line affecting the Error object.

Also, notice with NotImplementedError2, when I don't set the .name explicitly, it is equal to "Error". However, as mentioned in the comments, because that version sets prototype to new Error(), I could set NotImplementedError2.prototype.name = "NotImplementedError2" and be OK.