How do I determine if an Enum value has one or more of the values it's being compared with?

You can do that by combining values with | and checking via &.

To check if the value contains either of the tags:

if ((myValue & (Tag.PrimaryNav | Tag.HomePage)) != 0) { ... }

The | combines the enums you're testing (bitwise) and the & tests via bitwise masking -- if the result isn't zero, it has at least one of them set.

If you want to test whether it has both of them set, you can do that as well:

Tag desiredValue = Tag.PrimaryNav | Tag.HomePage;
if ((myValue & desiredValue) == desiredValue) { ... }

Here we're masking off anything we don't care about, and testing that the resulting value equals what we do care about (we can't use != 0 like before because that would match either value and here we're interested in both).

Some links:

• The & Operator
• The | Operator

You can use the HasFlag Method to avoid the need for the boolean logic,

Tag Val = (Tag)9;

if (Val.HasFlag(Tag.PrimaryNav))
{
    Console.WriteLine("Primary Nav");
}

if(Val.HasFlag(Tag.HomePage))
{
    Console.WriteLine("Home Page");
}

For bitwise (Flags) enums, an "any of" test is != 0, so:

const Tag flagsToLookFor = Tag.PrimaryNav | Tag.HomePage;
if ((node.Tag & flagsToLookFor) != 0) {
    // has some cross-over with PrimaryNav or HomePage (and possibly others too) 
}