How do I draw a Diagonal div?

You could use CSS3 transform skewY() function with positive value for the parent and negative value for the child wrapper element to achieve the effect.

.parent {
  -webkit-transform: skewY(-5deg);
  -moz-transform: skewY(-5deg);
  -ms-transform: skewY(-5deg);
  -o-transform: skewY(-5deg);
  transform: skewY(-5deg);
}

.parent > .child {
  -webkit-transform: skewY(5deg);
  -moz-transform: skewY(5deg);
  -ms-transform: skewY(5deg);
  -o-transform: skewY(5deg);
  transform: skewY(5deg);
}

WORKING DEMO.

From the spec:

skewY() specifies a 2D skew transformation along the Y axis by the given angle.

It's worth noting that the using skewY() won't change the width of the transformed elements.

Also mind the child selector. It's better to use direct child selector .parent > .child rather than descendant selector to negate the transform on the child element.


Really cool codes using background-image: https://codepen.io/PositionRelativ/pen/Ichrg

 .one{
   background-color: #013A6B;
   background-image: -webkit-linear-gradient(30deg, #013A6B 50%, #004E95 50%);
   min-height: 500px;
 }

I have used clip-path to get the same result. here is my code

body
{
	margin: 0;
	padding: 0;
}
.polygon
{
	height: 100vh;
	background: #00A2E8;
	clip-path: polygon(0 50%, 100% 0,100% 50%,0 100%);
	position: relative;
}
.content
{
	position: absolute;
	top: 50%;
	left: 20%;
}
<html>
	<head>
		<title>Clippath</title>
		<link rel="stylesheet" type="text/css" href="clip.css">
	</head>
	<body>
		<div class="polygon">
			<div class="content">
			<h2 class="head">heading</h2>
			<p>lorem ipsum dolar sit amet lol</p>
			</div>
		
		</div>
	</body>
</html>

Tags:

Html

Css

Recent Posts