How do I include negative decimal numbers in this regular expression?

You should add an optional hyphen at the beginning by adding -? (? is a quantifier meaning one or zero occurrences):

^-?[0-9]\d*(\.\d+)?$

I verified it in Rubular with these values:

10.00
-10.00

and both matched as expected.

let r = new RegExp(/^-?[0-9]\d*(\.\d+)?$/);

//true
console.log(r.test('10'));
console.log(r.test('10.0'));
console.log(r.test('-10'));
console.log(r.test('-10.0'));
//false
console.log(r.test('--10'));
console.log(r.test('10-'));
console.log(r.test('1-0'));
console.log(r.test('10.-'));
console.log(r.test('10..0'));
console.log(r.test('10.0.1'));

Some Regular expression examples:

Positive Integers:

^\d+$

Negative Integers:

^-\d+$

Integer:

^-?\d+$

Positive Number:

^\d*\.?\d+$

Negative Number:

^-\d*\.?\d+$

Positive Number or Negative Number:

^-?\d*\.{0,1}\d+$

Phone number:

^\+?[\d\s]{3,}$

Phone with code:

^\+?[\d\s]+\(?[\d\s]{10,}$

Year 1900-2099:

^(19|20)[\d]{2,2}$

Date (dd mm yyyy, d/m/yyyy, etc.):

^([1-9]|0[1-9]|[12][0-9]|3[01])\D([1-9]|0[1-9]|1[012])\D(19[0-9][0-9]|20[0-9][0-9])$

IP v4:

^(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5]){3}$