How do I store all results from an SQL query in a multidimensional array?

$data = array(); // create a variable to hold the information
while (($row = mysql_fetch_array($result, MYSQL_ASSOC)) !== false){
  $data[] = $row; // add the row in to the results (data) array
}

print_r($data); // print result

Update Feb '17 Now that it's 2017, it's advised you use PDOs over mysql_*. A lot safer and can return this natively with fetchAll (as shown in `TrexXx's answer).


$row = array();
$row[] = mysql_fetch_array($result, MYSQL_ASSOC);

Normally you'd assign the results like this in a loop

$rows = array();
while ($result = mysql_fetch_array($result, MYSQL_ASSOC)) {       
    $rows[] = $result;
}

If you need to store all rows returned by the query in an array, try this:

$result = array(); 

while ( $row = mysql_fetch_array($result, MYSQL_ASSOC) ){
    $result[] = $row
}

The only way to avoid doing a loop would to use PDO (PHP Data Objects) which is a better way to access database in PHP and you could do this :

$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '');
    
$q = $pdo->query('select * from yourtable');
$r = $q->fetchAll();
    
var_dump($r);

Tags:

Sql

Php