How do you find the disk size of a Postgres / PostgreSQL table and its indexes
Try the Database Object Size Functions. An example:
SELECT pg_size_pretty(pg_total_relation_size('"<schema>"."<table>"'));
For all tables, something along the lines of:
SELECT
table_schema || '.' || table_name AS table_full_name,
pg_size_pretty(pg_total_relation_size('"' || table_schema || '"."' || table_name || '"')) AS size
FROM information_schema.tables
ORDER BY
pg_total_relation_size('"' || table_schema || '"."' || table_name || '"') DESC;
Edit: Here's the query submitted by @phord, for convenience:
SELECT
table_name,
pg_size_pretty(table_size) AS table_size,
pg_size_pretty(indexes_size) AS indexes_size,
pg_size_pretty(total_size) AS total_size
FROM (
SELECT
table_name,
pg_table_size(table_name) AS table_size,
pg_indexes_size(table_name) AS indexes_size,
pg_total_relation_size(table_name) AS total_size
FROM (
SELECT ('"' || table_schema || '"."' || table_name || '"') AS table_name
FROM information_schema.tables
) AS all_tables
ORDER BY total_size DESC
) AS pretty_sizes;
I've modified it slightly to use pg_table_size()
to include metadata and make the sizes add up.
Show database sizes:
\l+
e.g.
=> \l+
berbatik_prd_commerce | berbatik_prd | UTF8 | en_US.UTF-8 | en_US.UTF-8 | | 19 MB | pg_default |
berbatik_stg_commerce | berbatik_stg | UTF8 | en_US.UTF-8 | en_US.UTF-8 | | 8633 kB | pg_default |
bursasajadah_prd | bursasajadah_prd | UTF8 | en_US.UTF-8 | en_US.UTF-8 | | 1122 MB | pg_default |
Show table sizes:
\d+
e.g.
=> \d+
public | tuneeca_prd | table | tomcat | 8192 bytes |
public | tuneeca_stg | table | tomcat | 1464 kB |
Only works in psql
.
(Summary of @zkutch's answer.)
If the database name is snort
, the following sentence give it size:
psql -c "\l+ snort" | awk -F "|" '{print $7}'