How many NULL pointers a doubly linked list can have at minimum? code example
Example: doubly linked list python
class ListNode:
def __init__(self, value, prev=None, next=None):
self.prev = prev
self.value = value
self.next = next
class DoublyLinkedList:
def __init__(self, node=None):
self.head = node
self.tail = node
self.length = 1 if node is not None else 0
def __len__(self):
return self.length
def add_to_head(self, value):
new_node = ListNode(value, None, None)
self.length += 1
if not self.head and not self.tail:
self.head = new_node
self.tail = new_node
else:
new_node.next = self.head
self.head.prev = new_node
self.head = new_node
def remove_from_head(self):
value = self.head.value
self.delete(self.head)
return value
def add_to_tail(self, value):
new_node = ListNode(value, None, None)
self.length += 1
if not self.tail and not self.head:
self.tail = new_node
self.head = new_node
else:
new_node.prev = self.tail
self.tail.next = new_node
self.tail = new_node
def remove_from_tail(self):
value = self.tail.value
self.delete(self.tail)
return value
def move_to_front(self, node):
if node is self.head:
return
value = node.value
if node is self.tail:
self.remove_from_tail()
else:
node.delete()
self.length -= 1
self.add_to_head(value)
def move_to_end(self, node):
if node is self.tail:
return
value = node.value
if node is self.head:
self.remove_from_head()
self.add_to_tail(value)
else:
node.delete()
self.length -= 1
self.add_to_tail(value)
def delete(self, node):
self.length -= 1
if not self.head and not self.tail:
return
if self.head == self.tail:
self.head = None
self.tail = None
elif self.head == node:
self.head = node.next
node.delete()
elif self.tail == node:
self.tail = node.prev
node.delete()
else:
node.delete()
def get_max(self):
if not self.head:
return None
max_val = self.head.value
current = self.head
while current:
if current.value > max_val:
max_val = current.value
current = current.next
return max_val